#include <bits/stdc++.h> #define pii pair <int,int> #define sc scanf #define pf printf #define Pi 2*acos(0.0) #define ms(a,b) memset(a, b, sizeof(a)) #define pb(a) push_back(a) #define MP make_pair #define db double #define ll long long #define EPS 10E-10 #define ff first #define ss second #define sqr(x) (x)*(x) #define D(x) cout<<#x " = "<<(x)<<endl #define VI vector <int> #define DBG pf("Hi\n") #define MOD 100007 #define MAX 100010 #define CIN ios_base::sync_with_stdio(0); cin.tie(0) #define SZ(a) (int)a.size() #define sf(a) scanf("%d",&a) #define sff(a,b) scanf("%d%d",&a,&b) #define sfff(a,b,c) scanf("%d%d%d",&a,&b,&c) #define loop(i,n) for(int i=0;i<n;i++) #define REP(i,a,b) for(int i=a;i<b;i++) #define TEST_CASE(t) for(int z=1;z<=t;z++) #define PRINT_CASE printf("Case %d:\n",z) #define all(a) a.begin(),a.end() #define intlim 2147483648 #define inf 1000000 #define ull unsigned long long using namespace std; int tree[3*MAX]; char str[MAX]; int n,m; void init_and_update(int node, int b, int e, int i, int j) { if(b>=i && e<=j) { tree[node]++; return; } int left=node*2; int right=left+1; int mid=(b+e)/2; if(j<=mid) init_and_update(left,b,mid,i,j); else if(i>mid) init_and_update(right,mid+1,e,i,j); else { init_and_update(left,b,mid,i,mid); init_and_update(right,mid+1,e,mid+1,j); } } int query(int node, int b, int e, int target) { if(b==target && e==target) { return tree[node]; } int left=node*2; int right=left+1; int mid=(b+e)/2; if(target<=mid) return tree[node]+query(left,b,mid,target); else return tree[node]+query(right,mid+1,e,target); } int main() { ///freopen("in.txt","r",stdin); ///freopen("out.txt","w",stdout); int t; sf(t); TEST_CASE(t) { ms(tree,0); sc("%s",str); sf(m); n=strlen(str); loop(i,n) if(str[i]=='1') init_and_update(1,1,n,i+1,i+1); PRINT_CASE; while(m--) { getchar(); char ch; sc("%c",&ch); if(ch=='I') { int a,b; sff(a,b); init_and_update(1,1,n,a,b); } else { int a; sf(a); pf("%d\n",query(1,1,n,a)%2); } } } return 0; }
[…] Another solution using segment tree is here -> 1080 – Binary Simulation(Segment Tree) […]