Problem Link : https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=show_problem&problem=2078
Github Link : https://github.com/tanmoy13/Uva/tree/master/11137—Ingenuous-Cubrency
Solution Idea:
This is a classical coin change problem and this can be solved using dp. Here the coins value are the cubic value of 1 to 21. we take a array called dp[] which size is greater than the maximum amount of input value. At first dp array contains only 0. Now we set dp[0]=1 because we can make 0 in 1 way and that is 0 😛 .
Now we run a loop via i and j for all index where i control coins value and j controls dp array index and calculate this…
dp[j]+=dp[j-coins[i]]
After this iteration we just take input and print the value of the dp array at that input index.
/* +-+ +-+ +-+ |R| |.| |S| +-+ +-+ +-+ */ #include <bits/stdc++.h> #define pii pair <int,int> #define sc scanf #define pf printf #define Pi 2*acos(0.0) #define ms(a,b) memset(a, b, sizeof(a)) #define pb(a) push_back(a) #define MP make_pair #define db double #define ll long long #define EPS 10E-10 #define ff first #define ss second #define sqr(x) (x)*(x) #define D(x) cout<<#x " = "<<(x)<<endl #define VI vector <int> #define DBG pf("Hi\n") #define MOD 100007 #define MAX 10000 #define CIN ios_base::sync_with_stdio(0); cin.tie(0) #define SZ(a) (int)a.size() #define sf(a) scanf("%d",&a) #define sfl(a) scanf("%lld",&a) #define sff(a,b) scanf("%d %d",&a,&b) #define sffl(a,b) scanf("%lld %lld",&a,&b) #define sfff(a,b,c) scanf("%d %d %d",&a,&b,&c) #define sfffl(a,b,c) scanf("%lld %lld %lld",&a,&b,&c) #define loop(i,n) for(int i=0;i<n;i++) #define REP(i,a,b) for(int i=a;i<b;i++) #define TEST_CASE(t) for(int z=1;z<=t;z++) #define PRINT_CASE printf("Case %d: ",z) #define all(a) a.begin(),a.end() #define intlim 2147483648 #define inf 1000000 #define ull unsigned long long using namespace std; /*----------------------Graph Moves----------------*/ //const int fx[]={+1,-1,+0,+0}; //const int fy[]={+0,+0,+1,-1}; //const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1}; // Kings Move //const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1}; // Kings Move //const int fx[]={-2, -2, -1, -1, 1, 1, 2, 2}; // Knights Move //const int fy[]={-1, 1, -2, 2, -2, 2, -1, 1}; // Knights Move /*------------------------------------------------*/ /*-----------------------Bitmask------------------*/ //int Set(int N,int pos){return N=N | (1<<pos);} //int reset(int N,int pos){return N= N & ~(1<<pos);} //bool check(int N,int pos){return (bool)(N & (1<<pos));} /*------------------------------------------------*/ ll dp[10100]; int coins[30]; int main() { ///freopen("in.txt","r",stdin); ///freopen("out.txt","w",stdout); REP(i,1,22) coins[i]=sqr(i)*i; dp[0]=1; for(int i=1;i<22;i++) { for(int j=coins[i];j<10100;j++) if(dp[j-coins[i]]) dp[j]+=dp[j-coins[i]]; } int n; while(sf(n)==1) { pf("%lld\n",dp[n]); } return 0; }
[…] problem is same as UVa 11137 – Ingenuous Cubrency . In this problem just the value of coins are changed and rest of the things is similar. you can […]